Preparation for Midterm Assessment Physics XI 2024-2025

1. Examples of Vector Quantities: - Displacement - Velocity - Acceleration - Force - Momentum - Electric Field Examples of Scalar Quantities: - Mass - Time - Temperature - Energy - Work - Power 2. Drawing the Vector Graphic: a. $\overrightarrow {R}=\overrightarrow {M}+\overrightarrow {N}+\overrightarrow {P}$ b. $\overrightarrow {R}=\overrightarrow {M}+\overrightarrow {N}-\overrightarrow {P}$ c. $\overrightarrow {R}=\overrightarrow {M}-\overrightarrow {N}-\overrightarrow {P}$ To draw the vector graphic using the head-to-tail method, start by drawing each vector with its corresponding direction and magnitude. Then, connect the tail of one vector to the head of the next vector, and repeat this process for all vectors in the equation. Finally, draw the resultant vector starting from the tail of the first vector and ending at the head of the last vector. 3. Determining the Equation Based on the Vector Graphic: i. $\square $ Without the graphic, it is not possible to determine the equation. Please provide the graphic for further assistance. 4. Determining the Magnitude of Vector Components: To determine the magnitude of the vector components on the x-axis and y-axis, decompose the vector into its horizontal and vertical components. Use trigonometric functions such as sine and cosine to find the magnitudes of these components. 5. Magnitude of Resultant Force on x-axis: The magnitude of the resultant force on the x-axis can be found by adding the magnitudes of the individual forces acting on the object along the x-axis. 6. Calculating the Resultant Force: Given two vectors of force, 12 N and 16 N, acting simultaneously on a body with an angle of $90^{\circ}$, the resultant force can be calculated using the Pythagorean theorem. The magnitude of the resultant force is $\sqrt{12^2 + 16^2} = 20$ N. 7. Determining the Magnitude of Vectors: a. $F1x$ and $F1y$ b. $F3x$ and $F3y$ c. $\sum Fx$ and $\sum Fy$ Without the specific values or diagram, it is not possible to determine the magnitudes of these vectors. Please provide the necessary information for further assistance. 8. Finding the Magnitude of Resultant Vector Using Cosine Formula: The magnitude of the resultant vector can be found using the cosine formula, which relates the magnitudes of the individual vectors and the angle between them. The formula is given by $R = \sqrt{A^2 + B^2 + 2AB\cos(\theta)}$, where A and B are the magnitudes of the individual vectors, and $\theta$ is the angle between them. 9. Finding the Angle Formed by Two Vectors: Given two vectors A = 10 and B = 4 with a resultant of $6\sqrt{5}$ N, the angle formed by the two vectors can be found using the dot product formula. The formula is given by $\cos(\theta) = \frac{A \cdot B}{|A||B|}$, where A and B are the magnitudes of the vectors, and $\theta$ is the angle between them. 10. Determining Total Distance, Displacement, Speed, and Velocity: a. Total distance: Add up the distances traveled in each direction. b. Displacement: Calculate the straight-line distance between the starting point and the final point. c. Speed: Calculate the average speed by dividing the total distance by the total time taken. d. Velocity: Calculate the average velocity by dividing the displacement by the total time taken. 11. Determining the Velocity of Object A: Given that object A is moving to the right with a velocity V and object B is moving to the left with a velocity of 8 m/s, and they meet after B has covered 320 m, the velocity of A can be found using the equation $V = \frac{960 - 320}{t}$, where t is the time taken for B to cover 320 m. Solving for t, we get $t = \frac{640}{8} = 80$ s. Therefore, the velocity of A is $V = \frac{640}{80} = 8$ m/s. 12. Formulas of Linear Motion with Constant Acceleration: - $v = u + at$ - $s = ut + \frac{1}{2}at^2$ - $v^