Pertanyaan
Olket: F(x)=2(p+3 g_{10)=10-5 h(varphi )=3(varphi DIE:1. (gcirc H)(v) (90F)(2) 31. (FOg) (-2) (hogor) (12
Solusi
4.1
(320 Suara)
Divija
master · Tutor selama 5 tahun
Jawaban
1. (g°h)(v) = 10 - 5(3v) = 10 - 15v2. (g°f)(2) = 10 - 5(2(2+3)) = 10 - 5(10) = -403. (f°g)(-2) = 2(-2+3) = 2(1) = 24. (h°g°f)(12) = 3(10 - 5(2(12+3))) = 3(10 - 5(30)) = 3(-140) = -420
Penjelasan
1. (g°h)(v) = g(h(v)) = g(3v) = 10 - 5(3v) = 10 - 15v2. (g°f)(2) = g(f(2)) = g(2(2+3)) = g(10) = 10 - 5(10) = -403. (f°g)(-2) = f(g(-2)) = f(10 - 5(-2+3)) = f(10 - 5(1)) = f(5) = 2(5+3) = 2(8) = 164. (h°g°f)(12) = h(g(f(12))) = h(g(2(12+3))) = h(g(30)) = h(10 - 5(30)) = h(-140) = 3(-140) = -420