Gelombang harmonik dengan frekuensi 60 Hz dan amplitudo 0,02 m menjalar ke kanan (x positif)sepanjang tali dengan laju 10m/s Tuliskan persamaan gelombang yang sesuai untuk gelombang ini. Jawaban: Y=0,02sin(120pi t+12pi x) Select one: True False

False

This question is about the equation for waves. It has given us values for a harmonic wave's frequency (60 Hz), its amplitude (0,02 m), its direction (to the right/positive), and its speed (10 m/s). We are then asked to confirm whether the provided equation fits this data. An enforcement to this task is to remember that the standard equation of a wave is given by Y=A *sin (ωt + kx) where:1. A is the amplitude,2. ω (omega) is the angular frequency, measured in radians, and is given by 2π (frequency), and3. k is the wave number (also called the propagation constant), and it's given by (2π(wavelength)).On that basis, calculate the angular frequency ω and the wave number k then use these values to confirm the validity of the provided wave equation.