EXEF CISE 4.3 During a new Moon, the Mum is alice.lly overhead in the middle of the day.(a) Final the grav italional force exerted by the Moon on a 70.0-kg man at the Earth's equator at noon. (3)Calculate the graviational force of the Moon on the man at midnight. (c) Calculate the difference in the man's acceration due to the Moon between noon and midnight. Note: The distance from the Earth to the Moon is 3.84times 10^8m The mass of the Moon is 7.36times 10^22kg ANSWERS (a) 2.41times 10^-3N (b) 2.25times 10^-3N (c) 2.3times 10^-6m/s^2 __

(a) 2.41×10^-3 N (b) 2.25×10^-3 N (c) 2.3×10^-6 m/s^2

This question is about gravitational force and its effects. (a) The gravitational force between two objects can be calculated using Newton's law of universal gravitation, which states that the force is equal to the gravitational constant (G) multiplied product of the two masses (m1 and m2), and divided by the square of the distance (r) between them. In this case, the gravitational constant G is 6.67430(15)×10−11 m3 kg−1 s−2, the mass of the man m1 is 70.0 kg, the mass of the Moon m2 is 7.36×10^22 kg, and the distance between the Earth and the Moon r is 3.84×10^8 m. (b) The same formula is used for calculating the gravitational force at midnight, but the distance between the Earth and the Moon is different because the Moon is on the opposite side of the Earth. The distance is now the diameter of the Earth plus the distance from the Earth to the Moon, which is 1.26×10^7 m + 3.84×10^8 m = 4.106×10^8 m.(c) The difference in the man's acceleration due to the Moon between noon and midnight is calculated by subtracting the acceleration at midnight from the acceleration at noon. The acceleration is the gravitational force divided by the man's mass.