Suatu reaksi berlangsung selama 3 menit pada suhu kamar.waktu yang diperlukar jika reaksi berlangsung pada suhu 61^circ C (setiap kenaikan 12^circ C reaksi berlangsung dua kali lebih cepat)

Here's how to solve this problem:**1. Understand the Rate Change:**The problem states that for every 12°C increase in temperature, the reaction rate doubles.**2. Calculate the Temperature Difference:**The temperature increased from room temperature (assumed to be 25°C) to 61°C. The difference is 61°C - 25°C = 36°C.**3. Determine the Number of Doubling Periods:**The temperature increased by 36°C. Since each 12°C increase doubles the rate, there are 36°C / 12°C/doubling = 3 doubling periods.**4. Calculate the Time Reduction:**Each doubling period halves the reaction time. Since there are 3 doubling periods, the reaction time will be reduced by a factor of 2³ = 8.**5. Calculate the New Reaction Time:**The original reaction time was 3 minutes. The new reaction time at 61°C will be 3 minutes / 8 = 0.375 minutes.**6. Convert to a More Convenient Unit (Optional):**0.375 minutes is equal to 0.375 minutes * 60 seconds/minute = 22.5 seconds.**Therefore, the reaction will take approximately 0.375 minutes (or 22.5 seconds) at 61°C.**