64. Diberikan data beberapa unsur transisi periode- UNSUR & BILANGAN OKSIDASI Q & +3 R & +1,+2,+3 S & +2,+3,+4,+5 T & +3,+4,+5,+6,+7 Spesi yang mungkin adalah (A) mathrm(QCl)_(2) (B) mathrm(RO)_(3)^2+ mathrm(X) (C) mathrm(SH)_(2)^- (D) mathrm(T)(mathrm(NO)_(3))_(2) (E) mathrm(TBr)_(5)( )^2-

### (E)

## Step 1: Identify the oxidation states of each element### From the table, we have the following oxidation states for each element:- Q: +3- R: +1, +2, +3- S: +2, +3, +4, +5- T: +3, +4, +5, +6, +7## Step 2: Determine the possible compounds based on oxidation states### We need to check if the given compounds can exist based on the oxidation states of the elements involved.### (A) :- For to be valid, Q would need an oxidation state of +2. However, Q only has an oxidation state of +3. Therefore, is not a valid compound.### (B) :- For to be valid, R would need an oxidation state of +6 (since oxygen typically has an oxidation state of -2). However, R only has oxidation states of +1, +2, and +3. Therefore, is not a valid compound.### (C) :- For to be valid, S would need an oxidation state of -2 (since hydrogen typically has an oxidation state of +1). However, S does not have a negative oxidation state; it only has positive oxidation states (+2, +3, +4, +5). Therefore, is not a valid compound.### (D) :- For to be valid, T would need an oxidation state of +2 (since nitrate, , has a charge of -1). However, T does not have an oxidation state of +2; it has oxidation states of +3, +4, +5, +6, +7. Therefore, is not a valid compound.### (E) :- For to be valid, T would need an oxidation state of +5 (since bromine typically has an oxidation state of -1). T has an oxidation state of +5, which makes a valid compound.