A stone is released from rest from a high building on Earth Air resistance is negligible. What is its velocity when it has fallen 5 m?

Here's how to solve this problem:**Understanding the Concepts*** **Free Fall:** When an object falls under the influence of gravity alone (neglecting air resistance), it's in free fall.* **Acceleration due to Gravity:** On Earth, the acceleration due to gravity (g) is approximately 9.8 m/s². This means the object's velocity increases by 9.8 meters per second every second it falls.* **Kinematic Equations:** We can use the following kinematic equation to relate displacement, initial velocity, acceleration, and time: * d = v₀t + (1/2)at² Where: * d = displacement (5 m in this case) * v₀ = initial velocity (0 m/s since the stone is released from rest) * a = acceleration due to gravity (9.8 m/s²) * t = time (unknown)**Solving for Velocity**1. **Find the time (t):** * We need to find the time it takes for the stone to fall 5 meters. Let's rearrange the kinematic equation to solve for t: * d = (1/2)at² * t² = (2d) / a * t = √((2d) / a) * t = √((2 * 5 m) / 9.8 m/s²) * t ≈ 1.01 seconds2. **Calculate the final velocity (v):** * We can use another kinematic equation: * v = v₀ + at * v = 0 m/s + (9.8 m/s²)(1.01 s) * v ≈ 9.9 m/s**Answer:** The stone's velocity when it has fallen 5 meters is approximately **9.9 m/s**.