The X thermometer is designed by setting the temperature of melting ice on the -25^circ X temperature scale and the temperature of boiling water on the 125^circ X scale. If the Celsius thermometer shows a temperature scale of 60^circ then thermometer X points to a temperature : scale of __ a 65^circ X b. 85^circ X 75^circ X d. 95^circ X

Here's how to solve this problem:**1. Understand the Relationship**The X thermometer has a range of 150 degrees (125 - (-25) = 150) between the freezing point of water and the boiling point. The Celsius scale has a range of 100 degrees (100 - 0 = 100) between the same points.**2. Set up a Proportion**We can set up a proportion to find the corresponding temperature on the X scale:* (X temperature - (-25)) / 150 = (Celsius temperature - 0) / 100**3. Solve for X Temperature*** Substitute the given Celsius temperature (60 degrees): (X temperature + 25) / 150 = 60 / 100* Simplify: (X temperature + 25) / 150 = 3/5* Cross-multiply: 5(X temperature + 25) = 450* Expand: 5X temperature + 125 = 450* Subtract 125 from both sides: 5X temperature = 325* Divide both sides by 5: X temperature = 65**Answer:**The thermometer X points to a temperature of **65°X**. So the correct answer is **(a)**.