64. Diberikan data beberapa unsur transisi periode-4 UNSUR & BILANGAN OKSIDASI mathrm(Q) & +3 mathrm(R) & +1,+2,+3 mathrm(S) & +2,+3,+4,+5 mathrm(T) & +3,+4,+5,+6,+7 Spesi yang mungkin adalah (A) mathrm(QCl)_(2) (B) mathrm(RO)_(3)^2+ mathrm(X) (C) mathrm(SH)_(2)^3 (D) mathrm(T)(mathrm(NO)_(3))_(2) (E) mathrm(TBr)_(5)( )^2-

### (E)

## Step 1: Identify the possible oxidation states for each element### From the table, we know the oxidation states of each element:- Element Q: +3- Element R: +1, +2, +3- Element S: +2, +3, +4, +5- Element T: +3, +4, +5, +6, +7## Step 2: Analyze the given species and their feasibility based on oxidation states### We need to determine if the given species can exist based on the oxidation states of the elements involved.### Option (B) :- For to be stable, R must have an oxidation state that balances the charge of the ion.- Oxygen typically has an oxidation state of -2. Therefore, in , the total oxidation state contributed by oxygen is .- To balance this, R must have an oxidation state of +4 ( ).- However, R only has oxidation states of +1, +2, and +3. Thus, is not feasible.### Option (C) :- For , S must have an oxidation state that balances the hydrogen atoms.- Hydrogen typically has an oxidation state of +1. Therefore, in , the total oxidation state contributed by hydrogen is .- To balance this, S must have an oxidation state of -2.- However, S only has oxidation states of +2, +3, +4, and +5. Thus, is not feasible.### Option (D) :- For , T must have an oxidation state that balances the nitrate ions.- Nitrate ( ) has a charge of -1. Therefore, two nitrate ions contribute a total charge of .- To balance this, T must have an oxidation state of +2.- Since T has oxidation states of +3, +4, +5, +6, and +7, it cannot have an oxidation state of +2. Thus, is not feasible.### Option (E) :- For , T must have an oxidation state that balances the bromine atoms and the overall charge.- Bromine typically has an oxidation state of -1. Therefore, in , the total oxidation state contributed by bromine is .- To balance this, T must have an oxidation state of +3 ( ).- Since T has an oxidation state of +3, is feasible.