Dua muatan sejanis masing-masing sebesar 5times 10^circ C tolak menolak. Jika jarak kedua muatan 0.5cm besar gaya Coulomb yang dialam kedua muatan adalah __ (K=9times 10^circ Nm^2C^-2)

Question

Answer 1

Penjelasan:Dalam soal ini, kita diminta untuk menghitung besar gaya Coulomb yang dialami oleh dua muatan sejenis yang masing-masing sebesar

0.5cm

F = \frac{{k \cdot |q_1| \cdot |q_2|}}{{r^2}}

F

k

9\times 10^9 Nm^2C^{-2}

q_1

q_2

r

q_1 = q_2 = 5\times 10^{\circ }C

r = 0.5cm = 0.005m

F = \frac{{(9\times 10^9 Nm^2C^{-2}) \cdot (5\times 10^{\circ }C) \cdot (5\times 10^{\circ }C)}}{{(0.005m)^2}}

F = \frac{{(9\times 10^9 Nm^^{-2}) \cdot (25\times 10^{\circ }C^2)}}{{(0.005m)^2}}

F = \frac{{(9\times 10^9 Nm^2C^{-2}) \cdot (25\times 10^{\circ }C^2)}}{{(0.005m)^2}}

F = \frac{{(9\times 10^9 Nm^2C^{-2}) \cdot (25\times 10^{\circ }2)}}{{(0.005m)^2}}

F = \frac{{(9\times 10^9 Nm^2C^{-2}) \cdot (25\times 10^{\circ }C^2)}}{{(0.005m)^2}}

F = \frac{{(9\times 10^9 Nm^2C^{-2}) \cdot (imes 10^{\circ }C^2)}}{{(0.005m)^2}}

F = \frac{{(9\times 10^9 Nm^2C^{-2}) \cdot (25\times 10^{\circ }C^2)}}{{(0.005m)^2}}

F = \frac{{(9\times 10^9 Nm^22}) \cdot (25\times 10^{\circ }C^2)}}{{(0.005m)^2}}

F = \frac{{(9\times 10^9 Nm^2C^{-2}) \cdot (25\times 10^{\circ }C^2)}}{{(0.005m)^2}}

F = \frac{{(imes 10^9 Nm^2C^{-2}) \cdot (25\times 10^{\circ }C^2)}}{{(0.005m)^2}}

F = \frac{{(9\times 10^9 Nm^2C^{-2}) \cdot (25\times 10^{\circ }C^2)}}{{(0.005m}}

F = \frac{{(9\times 10^9 Nm

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