Jika nomor atom unsur B=5 dan nomor atom unsur Cl=17 Orbital hibrida yang terjadi pada molekul BCl3 adalah? Select one: a. SP3 b. SP3D c. SP d. SP2

d. SP2

The hybridization of an atom depends on the number of atomic orbitals in an element's atoms. Each atomic orbital will be hybridized to form a new hybrid orbital. We need to consider the number of valence electrons, atomic orbitals and lone pairs of atoms.In our question, we have molecule BCl3. B (Boron) has an atomic number of 5, meaning it has 3 valence electrons in the 2nd shell (configuration of Boron is 1s² 2s² 2p¹). Thus, three atomic orbitals are involved in the hybridization process (one 2s and two 2p orbitals). On the other hand, Cl (Chlorine) has atomic number 17, and has 7 valence electrons in the 3rd shell looking to form a single bond with Boron. Because B forms 3 identical bonds with Cl, B has thus used one 2s orbital as well as two 2p orbitals, (because there are 3 Cl atoms to bond with), causing hybridization at Boron.To sum up, Boron uses three atomic orbitals which equate to a new hybrid Sp² orbital.