Suatu hari, Carleen sedang berjalan di sekitar rumahnya dan ia melihat sebuah ban bekas yang tergeletak di gudangnya. Sontak,iapun mengingat kembali dengan masa kecilnya yang sering kali memainkan ban dengan cara menggelindingkannya. Ia pun meng gelindingkannya sekali lagi untuk mengenang masa kecilnya. Roda ban tersebut berputar dengan kecepatan 3 rpm (Rotasi per menit). Tentukanlah frekuensi dan periode dari roda ban tersebut! A. f=20Hz dan T=0,5s B. f=20Hz dan T=0,05s C. f=0,5Hz dan T=20s D. f=0,05Hz dan T=20s E. f=0.05Hz dan T=5s A B C D E

Here's how to solve this problem:**1. Understanding the terms:*** **Frequency (f):** The number of complete rotations (or cycles) per unit of time. The unit is Hertz (Hz), which is cycles per second.* **Period (T):** The time it takes for one complete rotation (or cycle). The unit is seconds (s).* **Relationship between frequency and period:** Frequency and period are inversely proportional. Their relationship is: f = 1/T or T = 1/f**2. Converting rpm to Hz:**The wheel rotates at 3 rpm (rotations per minute). To convert this to Hz (rotations per second), we divide by 60 (since there are 60 seconds in a minute):f = 3 rpm / 60 s/min = 0.05 Hz**3. Calculating the period:**Now we can calculate the period using the relationship between frequency and period:T = 1/f = 1 / 0.05 Hz = 20 s**4. Conclusion:**The frequency of the wheel is 0.05 Hz, and its period is 20 s. Therefore, the correct answer is **D**.