EXERCISE 4.13 An experimental rocket plane lands on skids on a dry lake bed.If it's traveling at 80.0m/s when it touches down, how far does it slide before coming to rest? Assame the corflicient of kinetic friction between the skids and the lake bed is 0,600. ANSW ER 544m

To solve this problem, we need to use the principles of physics, specifically the work-energy theorem. The work done by friction will be equal to the change in kinetic energy of the rocket plane.Given:- Initial velocity ( ) = 80.0 m/s- Final velocity ( ) = 0 m/s (since the plane comes to rest)- Coefficient of kinetic friction ( ) = 0.600- Acceleration due to gravity ( ) = 9.8 m/s² (standard value)First, let's calculate the initial kinetic energy ( ) of the rocket plane: Next, we need to find the frictional force ( ) acting on the skids: The work done by friction ( ) as the plane slides to a stop is given by: Where is the distance the plane slides before coming to rest. According to the work-energy theorem, the work done by friction is equal to the loss in kinetic energy: So, Substitute into the equation: Now, solve for : Notice that cancels out from the numerator and denominator: Plug in the values for , , and : Calculate the value: Therefore, the rocket plane slides approximately 544 meters before coming to rest.