Penjelasan:1. Mulailah dengan mengevaluasi ekspresi di dalam tanda kurung pertama:
. Ini dapat disederhanakan dengan mengalikan eksponen di pembilang dan penyebut: $(\frac {2a^{-3}}{b^{-3}})^{-3} = (\frac {2^{-3}a^{3}}{b^{3}})^{-3} = (\frac {1}{2a})^{-3} = (\frac {2a}{1})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1}{2a})^{-3} = (\frac {1