Tentukan persamaan garis singgung f(x)=x^2-1 di titik x=-1 Select one: y=-(1)/(2)x+(1)/(2) y=(1)/(2)x+(1)/(2) y=2x-2 y=-2x-2

D

We should find the tangent line of a curve at a specific point which is instructed in the question is known as a derivative of the function. To do that, firstly, the derivative of function f(x)=x^2-1 is calculated as f'(x)=2x.It means the slope of the tangent is equivalent to the value of derivative at pointed x which is in this case, equals -2 From this point, we can get the line equation (f(x) - f(a) = f'(a)(x - a)), in this problem is (y-(-1)=-2(x-(-1))) or we got the equation, y = -2x-1