Tugas Buatlah media agar miring sebanyak 15 tabung.. (Diket. sc 29g/L) 2 Buatlah media cawan sebanyak 40 cawan (Diket. BAP: 40 g/L 3 Buatlah media tabung padat sebanyak 30 tabung (SIM: 35,5g/L) 4 Hitunglah media gula-gula berikut, jika ingin membuat media cair sebanyak 6 sel (5 seri gula-gula . (Glukosa 12g/L : Maltosa: 24g/L ; Manitol : 22g/L Laktosa 27,7g/L : Sukrosa : 11,9g/L)

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Tugas Buatlah media agar miring sebanyak 15 tabung.. (Diket. sc 29g/L) 2 Buatlah media cawan sebanyak 40 cawan (Diket. BAP: 40 g/L 3 Buatlah media tabung padat sebanyak 30 tabung (SIM: 35,5g/L) 4 Hitunglah media gula-gula berikut, jika ingin membuat media cair sebanyak 6 sel (5 seri gula-gula . (Glukosa 12g/L : Maltosa: 24g/L ; Manitol : 22g/L Laktosa 27,7g/L : Sukrosa : 11,9g/L)

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Answer 1

* Konsentrasi agar yang dibutuhkan: 1.93 g/L

b. Media Cawan

* Dahui:
* Konsentrasi BAP: 40 g/L
* Volume total: 40 cawan x 10 mL = 400 mL

* Rumus:
* \(C_1V_1 = C_2V_2\)

* Perhitungan:
* \(40 \text{ g/L} \times 10 \text{ mL} = C_2 \times 400 \text{ mL}\)
* \(C_2 = \frac{40 \text{ g/L} \times 10 \text{ mL}}{400 \text{ mL}} = 1 \text{ g/L}\)

* Jawaban:
* Konsentrasi BAP yang dibutuhkan: 1 g/L

c. Media Tabung Padat

* Diketahui:
* Konsentrasi SIM: 35,5 g/L
* Volume total: 30 tabung x 10 mL = 300 mL

* Rumus:
* \(C_1V_1 = C_2V_2\)

* Perhitungan:
* \(35,5 \text{ g/L} \times 10 \text{ mL} = C_2 \times 300 \text{ mL}\)
* \(C_2 = \frac{35,5 \text{ g/L} \times 10 \text{ mL}}{300 \text{ mL}} = 1.1833 \text{ g/L}\)

* Jawaban:
* Konsentrasi SIM yang dibutuhkan: 1.1833 g/L

d. Media Gula

* Diketahui:
* Glukosa: 12 g/L
* Maltosa: 24 g/L
* Manitol: 22 g/L
* Laktosa: 27,7 g/L
* Sukrosa: 11,9 g/L
* Volume total: 6 set x 5 seri x 10 mL = 300 mL

* Rumus:
* \(C_1V_1 = C_2V_2\)

* Perhitungan:
* Untuk setiap gula:
* Glukosa: \(12 \text{ g/L} \times 10 \text{ mL} = C_2 \times 50 \text{ mL}\)
* \(C_2 ={12 \text{ g/L} \times 10 \text{ mL}}{50 \text{ mL}} = 2.4 \text{ g/L}\)
* Maltosa: \(24 \text{ g/L} \times 10 \text{ mL} = C_2 \times 50 \text{ mL}\)
* \(C_2 = \frac{24 \text{ g/L} \times 10 \text{ mL}}{50 \text{ mL}} = 4.8 \text{ g/L}\)
* Manitol: \(22 \text{ g/L} \times 10 \text{ mL} = C_2 \times 50 \text{ mL}\)
* \(C_2 = \frac{22 \text{ g/L} \times 10 \text{ mL}}{50 \text{ mL}} = 4.4 \text{ g/L}\)
* Laktosa: \(27,7 \text{ g/L} \times 10 \text{ mL} = C_2 \times 50 \text{ mL}\)
* \(C_2 = \frac{27,7 \text{ g \times 10 \text{ mL}}{50 \text{ mL}} = 5.54 \text{ g/L}\)
* Sukrosa: \(11,9 \text{ g/L} \times 10 \text{ mL} = C

Answer 2

a. Media Agar Miring**

* Diketahui:
* Konsentrasi agar: 29 g/L
* Volume total: 15 tabung x 10 mL = 150 mL

* Rumus:
* \(C_1V_1 = C_2V_2\)

* Perhitungan:
* \(29 \text{ g/L} \times 10 \text{ mL} = C_2 \times 150 \text{ mL}\)
* \(C_2 = \frac{29 \text{ g/L} \times 10 \text{ mL}}{150 \text{ mL}} = 1.93 \text{ g/L}\)

*

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