Suatu reaksi berlangsung selama 3 menit pada suhu kamar.waktu yang diperlukar jika reaksi berlangsung pada suhu 61^circ C (setiap kenaikan 12^circ C reaksi berlangsung dua kali lebih cepat)

Question

Pertanyaan

Suatu reaksi berlangsung selama 3 menit pada suhu kamar.waktu yang diperlukar jika reaksi berlangsung pada suhu 61^circ C (setiap kenaikan 12^circ C reaksi berlangsung dua kali lebih cepat)

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Answer 1

Here's how to solve this problem:

1. Understand the Rate Change:

The problem states that for every 12°C increase in temperature, the reaction rate doubles.

2. Calculate the Temperature Difference:

The temperature increased from room temperature (assumed to be 25°C) to 61°C. The difference is 61°C - 25°C = 36°C.

3. Determine the Number of Doubling Periods:

The temperature increased by 36°C. Since each 12°C increase doubles the rate, there are 36°C / 12°C/doubling = 3 doubling periods.

4. Calculate the Time Reduction:

Each doubling period halves the reaction time. Since there are 3 doubling periods, the reaction time will be reduced by a factor of 2³ = 8.

5. Calculate the New Reaction Time:

The original reaction time was 3 minutes. The new reaction time at 61°C will be 3 minutes / 8 = 0.375 minutes.

6. Convert to a More Convenient Unit (Optional):

0.375 minutes is equal to 0.375 minutes * 60 seconds/minute = 22.5 seconds.

Therefore, the reaction will take approximately 0.375 minutes (or 22.5 seconds) at 61°C.

Pertanyaan

Suatu reaksi berlangsung selama 3 menit pada suhu kamar.waktu yang diperlukar jika reaksi berlangsung pada suhu 61^circ C (setiap kenaikan 12^circ C reaksi berlangsung dua kali lebih cepat)

Jawaban

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