Let, N_(C) be the internal normal force acts in horizontal left direction at point C, Now, apply the horizontal force equilibrium condition at point C, sum F_(x)=0 N_(C)+A_(x)=0 N_(C)=-A_(x) N_(C)=-30kN

Question

Pertanyaan

Let, N_(C) be the internal normal force acts in horizontal left direction at point C, Now, apply the horizontal force equilibrium condition at point C, sum F_(x)=0 N_(C)+A_(x)=0 N_(C)=-A_(x) N_(C)=-30kN

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Answer 1

The provided solution is correct in terms of applying the horizontal force equilibrium condition at point C. However, it's important to understand the context and the meaning of the negative sign in the final result.

Here's a breakdown:

* Horizontal Force Equilibrium: The equation $\sum F_{x}=0$ states that the sum of all horizontal forces acting on a point must be zero for the point to be in equilibrium. This is a fundamental principle in statics.
* Applying the Principle: You correctly applied this principle to point C, considering the internal normal force $N_C$ acting to the left and the horizontal component of force $A_x$ acting to the right.
* Negative Sign: The negative sign in the result $N_C = -30 kN$ indicates that the direction of the internal normal force $N_C$ is opposite to the assumed direction. Since we initially assumed $N_C$ to be acting to the left, the negative sign means it's actually acting to the right.

In summary:

The solution correctly applies the horizontal force equilibrium principle. The negative sign in the result for $N_C$ simply indicates that the force acts in the opposite direction to what was initially assumed.

To make the solution even clearer, you could explicitly state:

"Therefore, the internal normal force $N_C$ at point C has a magnitude of 30 kN and acts to the right."

Pertanyaan

Let, N_(C) be the internal normal force acts in horizontal left direction at point C, Now, apply the horizontal force equilibrium condition at point C, sum F_(x)=0 N_(C)+A_(x)=0 N_(C)=-A_(x) N_(C)=-30kN

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