Jika nomor atom unsur B=5 dan nomor atom unsur Cl=17 Orbital hibrida yang terjadi pada molekul BCl3 adalah? Select one: a. SP3 b. SP3D c. SP d. SP2

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Jika nomor atom unsur B=5 dan nomor atom unsur Cl=17 Orbital hibrida yang terjadi pada molekul BCl3 adalah? Select one: a. SP3 b. SP3D c. SP d. SP2

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Answer 1

The hybridization of an atom depends on the number of atomic orbitals in an element's atoms. Each atomic orbital will be hybridized to form a new hybrid orbital. We need to consider the number of valence electrons, atomic orbitals and lone pairs of atoms.

In our question, we have molecule BCl3. B (Boron) has an atomic number of 5, meaning it has 3 valence electrons in the 2nd shell (configuration of Boron is 1s² 2s² 2p¹). Thus, three atomic orbitals are involved in the hybridization process (one 2s and two 2p orbitals).

On the other hand, Cl (Chlorine) has atomic number 17, and has 7 valence electrons in the 3rd shell looking to form a single bond with Boron. Because B forms 3 identical bonds with Cl, B has thus used one 2s orbital as well as two 2p orbitals, (because there are 3 Cl atoms to bond with), causing hybridization at Boron.

To sum up, Boron uses three atomic orbitals which equate to a new hybrid Sp² orbital.

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Jika nomor atom unsur B=5 dan nomor atom unsur Cl=17 Orbital hibrida yang terjadi pada molekul BCl3 adalah? Select one: a. SP3 b. SP3D c. SP d. SP2

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