(frac (3x-2)/(5-32x+1))((2x+1)/(3))x+4

Question

Pertanyaan

$(frac (3x-2)/(5-32x+1))((2x+1)/(3))x+4$

(frac (3x-2)/(5-32x+1))((2x+1)/(3))x+4

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Answer 1

To simplify the given expression, we can start by simplifying the fractions in the numerator and denominator.

First, let's simplify the fraction in the numerator:
$\frac{3x-2}{5-32x+1}$

To simplify this fraction, we need to find a common denominator. In this case, the common denominator is 5. So, we can rewrite the fraction as:
$\frac{(3x-2) \cdot 5}{(5-32x+1) \cdot 5}$

Simplifying the numerator, we get:
$15x - 10$

Next, let's simplify the fraction in the denominator:
$\frac{2x+1}{3}$

To simplify this fraction, we need to find a common denominator. In this case, the common denominator is 3. So, we can rewrite the fraction as:
$\frac{(2x+1) \cdot 3}{3 \cdot 3}$

Simplifying the numerator, we get:
$6x + 3$

Now, we can substitute these simplified fractions back into the original expression:
$\frac{15x - 10}{6x + 3}x + 4$

To simplify further, we can cancel out the common factor of x in the numerator and denominator:
$\frac{15 - \frac{10}{6x + 3}}{6 + \frac{3}{6x + 3}}x + 4$

Simplifying the fractions, we get:
$\frac{15 - \frac{5}{3x + 1}}{6 + \frac{1}{2x + 1}}x + 4$

Therefore, the simplified expression is:
$\frac{15 - \frac{5}{3x + 1}}{6 + \frac{1}{2x + 1}}x + 4$

Pertanyaan

(frac (3x-2)/(5-32x+1))((2x+1)/(3))x+4

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